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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Sum Root to Leaf Numbers in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the ProblemSum Root to Leaf Numbers– LeetCode Problem

Sum Root to Leaf Numbers– LeetCode Problem

Problem:

You are given the root of a binary tree containing digits from 0 to 9 only.

Each root-to-leaf path in the tree represents a number.

  • For example, the root-to-leaf path 1 -> 2 -> 3 represents the number 123.

Return the total sum of all root-to-leaf numbers. Test cases are generated so that the answer will fit in a 32-bit integer.

leaf node is a node with no children.

Example 1:

num1tree
Input: root = [1,2,3]
Output: 25
Explanation:
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Therefore, sum = 12 + 13 = 25.

Example 2:

num2tree
Input: root = [4,9,0,5,1]
Output: 1026
Explanation:
The root-to-leaf path 4->9->5 represents the number 495.
The root-to-leaf path 4->9->1 represents the number 491.
The root-to-leaf path 4->0 represents the number 40.
Therefore, sum = 495 + 491 + 40 = 1026.

Constraints:

  • The number of nodes in the tree is in the range [1, 1000].
  • 0 <= Node.val <= 9
  • The depth of the tree will not exceed 10.
Sum Root to Leaf Numbers– LeetCode Solutions
Sum Root to Leaf Numbers Solution in C++:
class Solution {
 public:
  int sumNumbers(TreeNode* root) {
    int ans = 0;

    dfs(root, 0, ans);

    return ans;
  }

 private:
  void dfs(TreeNode* root, int path, int& ans) {
    if (!root)
      return;
    if (!root->left && !root->right) {
      ans += path * 10 + root->val;
      return;
    }

    dfs(root->left, path * 10 + root->val, ans);
    dfs(root->right, path * 10 + root->val, ans);
  }
};
Sum Root to Leaf Numbers Solution in Java:
class Solution {
  public int sumNumbers(TreeNode root) {
    dfs(root, 0);

    return ans;
  }

  private int ans = 0;

  private void dfs(TreeNode root, int path) {
    if (root == null)
      return;
    if (root.left == null && root.right == null) {
      ans += path * 10 + root.val;
      return;
    }

    dfs(root.left, path * 10 + root.val);
    dfs(root.right, path * 10 + root.val);
  }
}
Sum Root to Leaf Numbers Solution in Python:
class Solution:
  def sumNumbers(self, root: Optional[TreeNode]) -> int:
    self.ans = 0

    def dfs(root: Optional[TreeNode], path: int) -> None:
      if not root:
        return
      if not root.left and not root.right:
        self.ans += path * 10 + root.val
        return

      dfs(root.left, path * 10 + root.val)
      dfs(root.right, path * 10 + root.val)

    dfs(root, 0)

    return self.ans

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