**LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Solutions in C++**

Hello **Programmers/Coders,** Today we are going to share ** solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python**. At Each Problem with Successful submission with

**all Test Cases Passed,**you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the **Plus One** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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**About LeetCode**

*LeetCode* is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews.

LeetCode is for **software engineers who are looking to practice technical questions and advance their skills**. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either *Easy*, *Medium*, or *Hard*.

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- Mathematics/Basic Logical Based Questions
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Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

** Link for the Problem** – Plus One– LeetCode Problem

Plus One– LeetCode Problem

**Problem:**

You are given a **large integer** represented as an integer array `digits`

, where each `digits[i]`

is the `i`

digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading ^{th}`0`

‘s.

Increment the large integer by one and return *the resulting array of digits*.

**Example 1:**

Input:digits = [1,2,3]Output:[1,2,4]Explanation:The array represents the integer 123. Incrementing by one gives 123 + 1 = 124. Thus, the result should be [1,2,4].

**Example 2:**

Input:digits = [4,3,2,1]Output:[4,3,2,2]Explanation:The array represents the integer 4321. Incrementing by one gives 4321 + 1 = 4322. Thus, the result should be [4,3,2,2].

**Example 3:**

Input:digits = [9]Output:[1,0]Explanation:The array represents the integer 9. Incrementing by one gives 9 + 1 = 10. Thus, the result should be [1,0].

**Constraints:**

`1 <= digits.length <= 100`

`0 <= digits[i] <= 9`

`digits`

does not contain any leading`0`

‘s.

Plus One– LeetCode Solutions

Plus One in C++:

class Solution { public: vectorplusOne(vector & digits) { for (int i = digits.size() - 1; i >= 0; --i) { if (digits[i] < 9) { ++digits[i]; return digits; } digits[i] = 0; } digits.insert(begin(digits), 1); return digits; } };

Plus One in Java:

class Solution { public int[] plusOne(int[] digits) { for (int i = digits.length - 1; i >= 0; i--) { if (digits[i] < 9) { ++digits[i]; return digits; } digits[i] = 0; } int[] ans = new int[digits.length + 1]; ans[0] = 1; return ans; } }

Plus One in Python:

class Solution: def plusOne(self, digits: List[int]) -> List[int]: for i in range(len(digits) - 1, -1, -1): if digits[i] < 9: digits[i] += 1 return digits digits[i] = 0 return [1] + digits