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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Merge Sorted Array in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the ProblemMerge Sorted Array– LeetCode Problem

Merge Sorted Array– LeetCode Problem

Problem:

You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively.

Merge nums1 and nums2 into a single array sorted in non-decreasing order.

The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ignored. nums2 has a length of n.

Example 1:

Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Explanation: The arrays we are merging are [1,2,3] and [2,5,6].
The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.

Example 2:

Input: nums1 = [1], m = 1, nums2 = [], n = 0
Output: [1]
Explanation: The arrays we are merging are [1] and [].
The result of the merge is [1].

Example 3:

Input: nums1 = [0], m = 0, nums2 = [1], n = 1
Output: [1]
Explanation: The arrays we are merging are [] and [1].
The result of the merge is [1].
Note that because m = 0, there are no elements in nums1. The 0 is only there to ensure the merge result can fit in nums1.

Constraints:

  • nums1.length == m + n
  • nums2.length == n
  • 0 <= m, n <= 200
  • 1 <= m + n <= 200
  • -109 <= nums1[i], nums2[j] <= 109
Merge Sorted Array– LeetCode Solutions
Merge Sorted Array Solution in C++:
class Solution {
 public:
  void merge(vector& nums1, int m, vector& nums2, int n) {
    int i = m - 1;      // nums1's index (actual nums)
    int j = n - 1;      // nums2's index
    int k = m + n - 1;  // nums1's index (next filled position)

    while (j >= 0)
      if (i >= 0 && nums1[i] > nums2[j])
        nums1[k--] = nums1[i--];
      else
        nums1[k--] = nums2[j--];
  }
};
Merge Sorted Array Solution in Java:
class Solution {
  public void merge(int[] nums1, int m, int[] nums2, int n) {
    int i = m - 1;     // nums1's index (actual nums)
    int j = n - 1;     // nums2's index
    int k = m + n - 1; // nums1's index (next filled position)

    while (j >= 0)
      if (i >= 0 && nums1[i] > nums2[j])
        nums1[k--] = nums1[i--];
      else
        nums1[k--] = nums2[j--];
  }
}
Merge Sorted Array Solution in Python:
class Solution:
  def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
    i = m - 1      # nums1's index (actual nums)
    j = n - 1      # nums2's index
    k = m + n - 1  # nums1's index (next filled position)

    while j >= 0:
      if i >= 0 and nums1[i] > nums2[j]:
        nums1[k] = nums1[i]
        k -= 1
        i -= 1
      else:
        nums1[k] = nums2[j]
        k -= 1
        j -= 1

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