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In this post, you will find the solution for the **Length of Last Word** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Length of Last Word– LeetCode Problem

Length of Last Word– LeetCode Problem

**Problem:**

Given a string `s`

consisting of some words separated by some number of spaces, return *the length of the last word in the string.*

A **word** is a maximal substring consisting of non-space characters only.

**Example 1:**

Input:s = "Hello World"Output:5Explanation:The last word is "World" with length 5.

**Example 2:**

Input:s = " fly me to the moon "Output:4Explanation:The last word is "moon" with length 4.

**Example 3:**

Input:s = "luffy is still joyboy"Output:6Explanation:The last word is "joyboy" with length 6.

**Constraints:**

`1 <= s.length <= 10`

^{4}`s`

consists of only English letters and spaces`' '`

.- There will be at least one word in
`s`

Length of Last Word– LeetCode Solutions

Length of Last Word in C++:

class Solution { public: int lengthOfLastWord(string s) { int i = s.length() - 1; while (i >= 0 && s[i] == ' ') --i; const int lastIndex = i; while (i >= 0 && s[i] != ' ') --i; return lastIndex - i; } };

Length of Last Word in Java:

class Solution { public int lengthOfLastWord(String s) { int i = s.length() - 1; while (i >= 0 && s.charAt(i) == ' ') --i; final int lastIndex = i; while (i >= 0 && s.charAt(i) != ' ') --i; return lastIndex - i; } }

Length of Last Word in Python:

class Solution: def lengthOfLastWord(self, s: str) -> int: i = len(s) - 1 while i >= 0 and s[i] == ' ': i -= 1 lastIndex = i while i >= 0 and s[i] != ' ': i -= 1 return lastIndex - i