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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Largest Rectangle in Histogram in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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Link for the ProblemLargest Rectangle in Histogram– LeetCode Problem

Largest Rectangle in Histogram– LeetCode Problem

Problem:

Given an array of integers heights representing the histogram’s bar height where the width of each bar is 1, return the area of the largest rectangle in the histogram.

Example 1:

histogram
Input: heights = [2,1,5,6,2,3]
Output: 10
Explanation: The above is a histogram where width of each bar is 1.
The largest rectangle is shown in the red area, which has an area = 10 units.

Example 2:

histogram 1
Input: heights = [2,4]
Output: 4

Constraints:

  • 1 <= heights.length <= 105
  • 0 <= heights[i] <= 104
Largest Rectangle in Histogram– LeetCode Solutions
Largest Rectangle in Histogram in C++:
class Solution {
 public:
  int largestRectangleArea(vector& heights) {
    int ans = 0;
    stack stack;

    for (int i = 0; i <= heights.size(); ++i) {
      while (!stack.empty() &&
             (i == heights.size() || heights[stack.top()] > heights[i])) {
        const int h = heights[stack.top()];
        stack.pop();
        const int w = stack.empty() ? i : i - stack.top() - 1;
        ans = max(ans, h * w);
      }
      stack.push(i);
    }

    return ans;
  }
};
Largest Rectangle in Histogram in Java:
class Solution {
  public int largestRectangleArea(int[] heights) {
    int ans = 0;
    Stack stack = new Stack<>();

    for (int i = 0; i <= heights.length; ++i) {
      while (!stack.isEmpty() && (i == heights.length || heights[stack.peek()] > heights[i])) {
        final int h = heights[stack.pop()];
        final int w = stack.isEmpty() ? i : i - stack.peek() - 1;
        ans = Math.max(ans, h * w);
      }
      stack.push(i);
    }

    return ans;
  }
}
Largest Rectangle in Histogram in Python:
class Solution:
  def largestRectangleArea(self, heights: List[int]) -> int:
    ans = 0
    stack = []

    for i in range(len(heights) + 1):
      while stack and (i == len(heights) or heights[stack[-1]] > heights[i]):
        h = heights[stack.pop()]
        w = i - stack[-1] - 1 if stack else i
        ans = max(ans, h * w)
      stack.append(i)

    return ans

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