**Letter Combinations of a Phone Number LeetCode Problem | LeetCode Problems For Beginners | LeetCode Problems & Solutions | Improve Problem Solving Skills | LeetCode Problems Java | LeetCode Problems C++**

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In this post, you will find the solution for the ** Letter Combinations of a Phone Number** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Letter Combinations of a Phone Number– LeetCode Problem

Letter Combinations of a Phone Number– LeetCode Problem

**Problem:**

Given a string containing digits from `2-9`

inclusive, return all possible letter combinations that the number could represent. Return the answer in **any order**.

A mapping of digits to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.

**Example 1:**

Input:digits = "23"Output:["ad","ae","af","bd","be","bf","cd","ce","cf"]

**Example 2:**

Input:digits = ""Output:[]

**Example 3:**

Input:digits = "2"Output:["a","b","c"]

**Constraints:**

`0 <= digits.length <= 4`

`digits[i]`

is a digit in the range`['2', '9']`

.

Letter Combinations of a Phone Number– LeetCode Solutions

class Solution { public: vectorletterCombinations(string digits) { if (digits.empty()) return {}; vector ans; dfs(digits, 0, "", ans); return ans; } private: const vector digitToLetters{"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; void dfs(const string& digits, int i, string&& path, vector & ans) { if (i == digits.length()) { ans.push_back(path); return; } for (const char letter : digitToLetters[digits[i] - '0']) { path.push_back(letter); dfs(digits, i + 1, move(path), ans); path.pop_back(); } } };

class Solution { public ListletterCombinations(String digits) { if (digits.isEmpty()) return new ArrayList<>(); List ans = new ArrayList<>(); ans.add(""); final String[] digitToLetters = {"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; for (final char d : digits.toCharArray()) { List temp = new ArrayList<>(); for (final String s : ans) for (final char c : digitToLetters[d - '0'].toCharArray()) temp.add(s + c); ans = temp; } return ans; } }

class Solution: def letterCombinations(self, digits: str) -> List[str]: if not digits: return [] ans = [''] digitToLetters = ['', '', 'abc', 'def', 'ghi', 'jkl', 'mno', 'pqrs', 'tuv', 'wxyz'] for d in digits: temp = [] for s in ans: for c in digitToLetters[ord(d) - ord('0')]: temp.append(s + c) ans = temp return