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In this post, you will find the solution for the **Jump Game** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Jump Game– LeetCode Problem

Jump Game– LeetCode Problem

**Problem:**

You are given an integer array `nums`

. You are initially positioned at the array’s **first index**, and each element in the array represents your maximum jump length at that position.

Return `true`

* if you can reach the last index, or *`false`

* otherwise*.

**Example 1:**

Input:nums = [2,3,1,1,4]Output:trueExplanation:Jump 1 step from index 0 to 1, then 3 steps to the last index.

**Example 2:**

Input:nums = [3,2,1,0,4]Output:falseExplanation:You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index.

**Constraints:**

`1 <= nums.length <= 10`

^{4}`0 <= nums[i] <= 10`

^{5}

Jump Game– LeetCode Solutions

Jump Game in C++:

class Solution { public: bool canJump(vector& nums) { int i = 0; for (int reach = 0; i < nums.size() && i <= reach; ++i) reach = max(reach, i + nums[i]); return i == nums.size(); } };

Jump Game in Java:

class Solution { public boolean canJump(int[] nums) { int i = 0; for (int reach = 0; i < nums.length && i <= reach; ++i) reach = Math.max(reach, i + nums[i]); return i == nums.length; } }

Jump Game in Python:

class Solution: def canJump(self, nums: List[int]) -> bool: i = 0 reach = 0 while i < len(nums) and i <= reach: reach = max(reach, i + nums[i]) i += 1 return i == len(nums)