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In this post, you will find the solution for the **Integer to Roman** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Integer to Roman– LeetCode Problem

Integer to Roman– LeetCode Problem

**Problem:**

Roman numerals are represented by seven different symbols: `I`

, `V`

, `X`

, `L`

, `C`

, `D`

and `M`

.

SymbolValueI 1 V 5 X 10 L 50 C 100 D 500 M 1000

For example, `2`

is written as `II`

in Roman numeral, just two one’s added together. `12`

is written as `XII`

, which is simply `X + II`

. The number `27`

is written as `XXVII`

, which is `XX + V + II`

.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not `IIII`

. Instead, the number four is written as `IV`

. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as `IX`

. There are six instances where subtraction is used:

`I`

can be placed before`V`

(5) and`X`

(10) to make 4 and 9.`X`

can be placed before`L`

(50) and`C`

(100) to make 40 and 90.`C`

can be placed before`D`

(500) and`M`

(1000) to make 400 and 900.

Given an integer, convert it to a roman numeral.

**Example 1:**

Input:num = 3Output:"III"Explanation:3 is represented as 3 ones.

**Example 2:**

Input:num = 58Output:"LVIII"Explanation:L = 50, V = 5, III = 3.

**Example 3:**

Input:num = 1994Output:"MCMXCIV"Explanation:M = 1000, CM = 900, XC = 90 and IV = 4.

**Constraints:**

Integer to Roman– LeetCode Solutions

class Solution { public: string intToRoman(int num) { const vectorM{"", "M", "MM", "MMM"}; const vector C{"", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM"}; const vector X{"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"}; const vector I{"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"}; return M[num / 1000] + C[num % 1000 / 100] + X[num % 100 / 10] + I[num % 10]; } };

class Solution { public String intToRoman(int num) { final String[] M = {"", "M", "MM", "MMM"}; final String[] C = {"", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM"}; final String[] X = {"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"}; final String[] I = {"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"}; return M[num / 1000] + C[num % 1000 / 100] + X[num % 100 / 10] + I[num % 10]; } }

class Solution: def intToRoman(self, num: int) -> str: M = ['', 'M', 'MM', 'MMM'] C = ['', 'C', 'CC', 'CCC', 'CD', 'D', 'DC', 'DCC', 'DCCC', 'CM'] X = ['', 'X', 'XX', 'XXX', 'XL', 'L', 'LX', 'LXX', 'LXXX', 'XC'] I = ['', 'I', 'II', 'III', 'IV', 'V', 'VI', 'VII', 'VIII', 'IX'] return M[num // 1000] + C[num % 1000 // 100] + X[num % 100 // 10] + I[num % 10]