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In this post, you will find the solution for the **Gray Code** **in C++, Java & Python-LeetCode problem**. We are providing the **correct and tested solutions** to coding problems present on **LeetCode**. If you are not able to solve any problem, then you can take help from our Blog/website.

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** Link for the Problem** – Gray Code– LeetCode Problem

**Gray Code– LeetCode Problem**

**Problem:**

An **n-bit gray code sequence** is a sequence of `2`

integers where:^{n}

- Every integer is in the
**inclusive**range`[0, 2`

,^{n}- 1] - The first integer is
`0`

, - An integer appears
**no more than once**in the sequence, - The binary representation of every pair of
**adjacent**integers differs by**exactly one bit**, and - The binary representation of the
**first**and**last**integers differs by**exactly one bit**.

Given an integer `n`

, return *any valid n-bit gray code sequence*.

**Example 1:**

Input:n = 2Output:[0,1,3,2]Explanation:The binary representation of [0,1,3,2] is [00,01,11,10]. - 00 and 01 differ by one bit - 01 and 11 differ by one bit - 11 and 10 differ by one bit - 10 and 00 differ by one bit [0,2,3,1] is also a valid gray code sequence, whose binary representation is [00,10,11,01]. - 00 and 10 differ by one bit - 10 and 11 differ by one bit - 11 and 01 differ by one bit - 01 and 00 differ by one bit

**Example 2:**

Input:n = 1Output:[0,1]

**Constraints:**

Gray Code– LeetCode Solutions

Gray Code Solution in C++:

class Solution { public: vectorgrayCode(int n) { vector ans{0}; for (int i = 0; i < n; ++i) for (int j = ans.size() - 1; j >= 0; --j) ans.push_back(ans[j] | 1 << i); return ans; } };

Gray Code Solution in Java:

class Solution { public ListgrayCode(int n) { List ans = new ArrayList<>(); ans.add(0); for (int i = 0; i < n; ++i) for (int j = ans.size() - 1; j >= 0; --j) ans.add(ans.get(j) | 1 << i); return ans; } }

Gray Code Solution in Python:

class Solution: def grayCode(self, n: int) -> List[int]: ans = [0] for i in range(n): for j in range(len(ans) - 1, -1, -1): ans.append(ans[j] | 1 << i) return ans