 # Day 10: Binary Numbers In Java | 30 Days Of Code | Hackerrank Programming Solutions

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Link for the ProblemDay 10: Binary Numbers – Hacker Rank Solution

`Day 10: Binary Numbers – Hacker Rank Solution`

### Problem:

Objective
Today, we’re working with binary numbers. Check out the Tutorial tab for learning materials and an instructional video!

Given a base- integer, , convert it to binary (base-). Then find and print the base- integer denoting the maximum number of consecutive ‘s in ‘s binary representation. When working with different bases, it is common to show the base as a subscript.

Example

The binary representation of  is . In base , there are  and  consecutive ones in two groups. Print the maximum, .

Input Format

A single integer, .

Constraints

Output Format

Print a single base- integer that denotes the maximum number of consecutive ‘s in the binary representation of .

Sample Input 1

```5
```

Sample Output 1

```1
```

Sample Input 2

```13
```

Sample Output 2

```2
```

Explanation

Sample Case 1:
The binary representation of  is , so the maximum number of consecutive ‘s is .

Sample Case 2:
The binary representation of  is , so the maximum number of consecutive ‘s is .

`Day 10: Binary Numbers – Hacker Rank Solution`
```import java.util.Scanner;

/**
* @author Techno-RJ
*
*/
public class Day10BinaryNumbers {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
in.close();
int r = n, counter = 0, maxOne = 0;
String s = "";
while (n > 0) {

r = n % 2;
if (r == 1) {
counter++;
if (counter > maxOne) {
maxOne = counter;
}
} else {
counter = 0;
}
s = r + s;
n = n / 2;

}
System.out.println(maxOne);

}
}```

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