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Hello Programmers/Coders, Today we are going to share solutions to the Programming problems of LeetCode Solutions in C++, Java, & Python. At Each Problem with Successful submission with all Test Cases Passed, you will get a score or marks and LeetCode Coins. And after solving maximum problems, you will be getting stars. This will highlight your profile to the recruiters.

In this post, you will find the solution for the Binary Tree Upside Down in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present on LeetCode. If you are not able to solve any problem, then you can take help from our Blog/website.

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About LeetCode

LeetCode is one of the most well-known online judge platforms to help you enhance your skills, expand your knowledge and prepare for technical interviews. 

LeetCode is for software engineers who are looking to practice technical questions and advance their skills. Mastering the questions in each level on LeetCode is a good way to prepare for technical interviews and keep your skills sharp. They also have a repository of solutions with the reasoning behind each step.

LeetCode has over 1,900 questions for you to practice, covering many different programming concepts. Every coding problem has a classification of either EasyMedium, or Hard.

LeetCode problems focus on algorithms and data structures. Here is some topic you can find problems on LeetCode:

  • Mathematics/Basic Logical Based Questions
  • Arrays
  • Strings
  • Hash Table
  • Dynamic Programming
  • Stack & Queue
  • Trees & Graphs
  • Greedy Algorithms
  • Breadth-First Search
  • Depth-First Search
  • Sorting & Searching
  • BST (Binary Search Tree)
  • Database
  • Linked List
  • Recursion, etc.

Leetcode has a huge number of test cases and questions from interviews too like Google, Amazon, Microsoft, Facebook, Adobe, Oracle, Linkedin, Goldman Sachs, etc. LeetCode helps you in getting a job in Top MNCs. To crack FAANG Companies, LeetCode problems can help you in building your logic.

Link for the ProblemBinary Tree Upside Down– LeetCode Problem

Binary Tree Upside Down– LeetCode Problem

Problem:

Given a binary tree where all the right nodes are either leaf nodes with a sibling (a left node that shares the same parent node) or empty, flip it upside down and turn it into a tree where the original right nodes turned into left leaf nodes. Return the new root.

For example:

Given a binary tree {1,2,3,4,5},

   1
  / 
 2   3
/ 
4 5

return the root of the binary tree [4,5,2,#,#,3,1].

 4
/ 
5  2
  / 
 3   1
Binary Tree Upside Down– LeetCode Solutions
Binary Tree Upside Down Solution in C++:
class Solution {
 public:
  TreeNode* upsideDownBinaryTree(TreeNode* root) {
    if (!root || !root->left)
      return root;

    TreeNode* newRoot = upsideDownBinaryTree(root->left);
    root->left->left = root->right;  // 2's left = 3 (root's right)
    root->left->right = root;        // 2's right = 1 (root)
    root->left = nullptr;
    root->right = nullptr;
    return newRoot;
  }
};
Binary Tree Upside Down Solution in Java:
class Solution {
  public TreeNode upsideDownBinaryTree(TreeNode root) {
    if (root == null || root.left == null)
      return root;

    TreeNode newRoot = upsideDownBinaryTree(root.left);
    root.left.left = root.right; // 2's left = 3 (root's right)
    root.left.right = root;      // 2's right = 1 (root)
    root.left = null;
    root.right = null;
    return newRoot;
  }
}
Binary Tree Upside Down Solution in Python:
class Solution:
  def upsideDownBinaryTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
    if not root or not root.left:
      return root

    newRoot = self.upsideDownBinaryTree(root.left)
    root.left.left = root.right  # 2's left = 3 (root's right)
    root.left.right = root  # 2's right = 1 (root)
    root.left = None
    root.right = None
    return newRoot

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